Have you ever wondered how to reverse the digits of a signed 32-bit integer in Java? Reversing the digits of an integer is a common programming task, and it's essential to handle it correctly, especially when dealing with constraints like the 32-bit integer range. In this blog post, we'll walk you through how to achieve this task in Java, ensuring that you handle potential integer overflow. The Challenge The challenge is to reverse the digits of a given 32-bit integer x while maintaining the constraints of the problem. In Java, an int can hold 32 bits, with values ranging from -2^31 to 2^31 - 1. Reversing the digits should be done while considering both positive and negative integers and avoiding integer overflow. The Java Solution To reverse the digits of a 32-bit integer in Java, you can follow these steps: java Copy code public int reverse ( int x) { // Initialize variables to store the result and check for the sign of x int result = 0 ; int sign = ...